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%TCIDATA{Created=Thursday, February 19, 2004 09:52:26}
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%$Q_{1}=\left( 94+95\right) /2=94.5$
%$Q_{3}=\left( 120+120\right) /2=120$
%}


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\begin{document}


creditos \ 119 15 73 114 93 120 \ 94 130 \ 97 64 98 \ 113 124 120 95 125 13
118 118 106 108 130 128

\bigskip 

Ordenar los datos

13

15

64

73

93

94 \ \ $\ \ \ \ Q_{1}=\left( 94+95\right) /2=94.5$

95

97

98

106

108

113 \ $\ \rightarrow \rightarrow \rightarrow $ \ mediana \ \ \ \ \ \ \ \ \ \
\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ $\
RIQ=Q_{3}-Q_{1}=120-94.5=\allowbreak 25.\,\allowbreak 5$

114

118

118 \ \ \ \ \ \ \ \ \ \ \ \ \ Fronteras Interiores = $\left(
Q_{1}-1.5RIQ,Q_{3}+1.5RIQ\right) =\allowbreak (94.5-1.5\ast 25.5,120+1.5\ast
25.5)=(56.25,158.25)\allowbreak $

119 \ \ \ \ \ \ \ \ \ \ \ \ \ Fronteras Exteriores = $\left(
Q_{1}-3RIQ,Q_{3}+3RIQ\right) =\allowbreak (94.5-3\ast 25.5,120+3\ast
25.5)=(18,196.5)$

120 \ $Q_{3}=\left( 120+120\right) /2=120$

120

124

125

128

130

130

\bigskip 

Por lo tanto 13 y 15 son outliers

\end{document}
